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Respuesta:
In both cases, use the linear equation to express one variable in terms of the other, and then substitute the dependent variable in the quadratic equation. This will give you a quadratic equation in one variable which you solve with the quadratic formula. I’ll do the first part of #1 for you, and then you can do the rest on your own.
x=3+2y , so, substituting,
(3+2y)2+2y2=27
9+12y+4y2+2y2=27
9+12y+6y2=27
3+4y+2y2=9
2y2+4y−6=0
y2+2y−3=0
Just remember the quadratic formula: for any variable x , any constants a,b,c , where ax2+bx+c=0 ,
x=−b±b2−4ac√2a
And plug it in, and solve for y . You can then use the linear equation with a known value of y to solve for x .
Explicación:
odethjohan:
Es correcto ??
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