Question

Resuelve las siguientes ecuaciones
x2 + 6x = 0
3x2 + x = 0
x2 - 6x = 0
x(6x + 3) = 0
x2 - 4x = 0
4 X2 - x = x2
4x(1 + x) = 0
2 x2 = 9 - X2
aiudaaaaaa plissss

Answer 1

Respuesta:

Explicación paso a paso:

x2 + 6x = 0

x(x+6) = 0  => x1=0  ; x2= -6

3x2 + x = 0

x(3x +1) = 0 => x1=0  ;  x2= -1/3

x2 - 6x = 0

x(x-6) = 0  => x1=0  ;  x2=6

x(6x + 3) = 0   => x1 =0  ;  x2= -3/6 = - 1/2

x2 - 4x = 0

x(x - 4) = 0  =>  x1 = 0  ;   x2 = 4

4 X2 - x = x2

3x² - x = 0  => x(3x - 1)=0  => x1=0  ;  x2 = 1/3

4x(1 + x) = 0   => x1=0  ;   x2 = -1

2 x2 = 9 - X2

3x² - 9 = 0

3x(x - 3) = 0  =>  x1=0   ;   x2 = 3