Question

derivar las funciones logaritmicas

f(x)=in(x+3)


f(x)=7x+in (x-3)
porfa me urge

f(x)=sen (x+1)


f(x)=in (x2-3x+2)

Answer 1

Respuesta:

Explicación:

f(x)=in(x+3)

f '(x) = (x+3)'/(x+3) = 1/(x+3)

f(x)=7x+in (x-3)

f '(x) = (7x+in (x-3))' = (7x)+(ln (x-3))'

= 7 + 1/(x+3)

f(x)=sen (x+1)

f '(x) = (x+1)' cos (x+1) = cos (x+1)

f(x)=in (x2-3x+2)

f '(x)= (x²-3x+2)'/(x²-3x+2)= (2x - 3)/(x²-3x+2)