Question

derivada de d(3x^2+x-10)​

Answer 1

$\frac{d}{dx}\left(3x^2+x-10\right)\\\\=\frac{d}{dx}\left(3x^2\right)+\frac{d}{dx}\left(x\right)-\frac{d}{dx}\left(10\right)\\\\=6x+1-0\\=6x+1$