Question

7 (2π+ 3√2) =
(7×2)π+(7×3)√2 =
14π+ 21√2) =
-4 (3/5+ 0,25-6π) =

(-4 ×3/5 )+(-4× 0,25)-(-4×6π) =
-12/5-1+24π =
(-12-5+120π)/5 =
-(17+120π)/5
porfavor me puden ayudar

Answer 1

Respuesta:

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Explicación paso a paso:

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