Question

como resolver 14X – (3X – 2) – [5X + 2 – (X – 1)] = 0

Answer 1

14x - (3x - 2) - [ 5x + 2 - (x-1)] = 0
14x - 3x + 2 - [ 5x + 2 - x + 1] = 0
11x + 2 - [ 4x + 3 ] = 0
11x + 2 - 4x - 3 = 0
7x - 1 = 0
7x = 1
x = 1/7

Answer 2

Resolver.

14x - ( 3x - 2) - [ 5x + 2 - (x - 1)] = 0
14x - 3x + 2 - [5x + 2 - x + 1] = 0
11x + 2 - [4x + 3] = 0
11x + 2 - 4x - 3 = 0
7x - 1 = 0
7x = 1
x = 1/7

Respuesta.
x = 1/7

Aplcamos ley de signos
+ por + = +
-  por  - = +
+ por  - = -
-  por  + = -