Question

determine el valor de "m" para que el sistema en X e y
5x+(3-m)y=4 sea incompatible
2x-(2-m)y=6​

Answer 1

Respuesta:

1) 5x-y = 9 5x - 9 = y

2x+y = 12 y = 12 - 2x

5x - 9 = 12 - 2x

7x = 21

x= 3

y = 12 -2(3) = 6

y = 6

2) 4x+2y = 26 y = 13 - 2x

x+3y=14 y = 14 -x / 3

13 - 2x = 14 -x / 3

39 - 6x = 14 - x

25 = 5x

x= 5

y = 13- 2(5)= 3

y= 3

3) x+y = -8 y = -8 -x

x-y = -2 x-2 = y

-8 -x =x-2

-6 = 2x

x= -3

-3 +y = -8

y = -5

4) x+2y = 2 y = 2- x / 2

-2x+3y = 10 y = 10+ 2x / 3

2- x / 2 = 10+ 2x / 3

6 -3x = 20 + 4x

-7x = 14

x= -2

y = 10+ 2(-2) / 3

y = 2

5) x+3y = 5 y = 5 -x / 3

5x-4y = 6 y = 5x -6 / 4

5 -x / 3 = 5x -6 / 4

20 - 4x = 15x -18

38 = 19x

x= 2

y = 5- 2/3

y= 1

1) 3x+7y = -17 x = -17 -7y / 3

5x-2y = -1

5( -17 -7y / 3) -2y = -1

-85 -35y -6y = -3

-82 = 41y

y= -2

x = -17 -7(-2) / 3

x = -1

2) 2x+y = 16 y= 16-2x

3x-3y = 6

reemplazando

3x - 3(16-2x) = 6

3x -48 +6x = 6

9x = 54

x= 6

y= 16-2(6)

y= 4

3) 3x-2y = -2 x = -2 +2y / 3

x+y = 6

reemplazando

-2 +2y / 3 + y = 6

-2 +2y+3y = 18

5y = 20

y = 4

x = -2 +2( 4) / 3

x= 2

4) 5x+2y = 40 x= 40 -2y / 5

-2x-5y = 26

reemplazando

-2(40 -2y / 5) -5y = 26

-80 +4y -25y = 130

-21y = 210

y= -10

x= 40 -2(-10) / 5

x= 12

5) 2x+3y = 13 x= 13 -3y / 2

4x-y = 5

reemplazando

4( 13 -3y / 2) -y = 5

26 -6y -y =5

21 = 7y

y = 3

x= 13 -3 (3) / 2

x= 2

Explicación paso a paso: