• Asignatura: Matemáticas
  • Autor: smithsanchez883
  • hace 6 años

ayundenmen porfavor es para hoy

(4 {m}^{n}  +  {y}^{n}  {)}^{2}
 (3 {a}^{n}  + 2 {b}^{n + 1}  {)}^{2}
(5 {y}^{m + 1}  - 2 {x}^{m}  {)}^{2}
(  \frac{1}{5}  {m}^{n + 1}  +  {m}^{n + 3}  {)}^{2}
( \frac{1}{7}  {y}^{2t + 1 }   -  \frac{1}{4}  {y}^{x + 2}  {)}^{2}
( \frac{4}{9}  {n}^{n}  +  {r}^{m}  {)}^{2}
(2b -  {c}^{x + 2}  {)}^{2}
(3.2 {m}^{2z + 1}  +  {m}^{z + 1}  +  {m}^{z + 2}  {)}^{2}
(5 \times \frac{1}{3}  {n}^{2 + x}  - 7 \times \frac{1}{2}  {m}^{3 + 2x}  {)}^{2}


mauriciobenavidesbau: Es mucho, divídelo en algunas preguntas y lo resuelvo :)

Respuestas

Respuesta dada por: mauriciobenavidesbau
1

Respuesta:

1.

(4m^{n} +y^{n})^{2}\\(4m^{n})^{2}+2(4m^{n})(y^{n})+(y^{n})^{2}\\16m^{2n} +8m^{n}y^{n}+y^{2n}

2.

(3a^{n} +2b^{n+1})^{2} \\(3a^{n})^{2} +2(3a^{n})(2b^{n+1})+(2b^{n+1})^{2} \\9a^{2n} +12a^{n} b^{n+1} +4b^{2n+2}

3.

(5y^{m+1} -2x^{m})^{2} \\(5y^{m+1})^{2} - 2(5y^{m+1})(2x^{m})+(2x^{m})^{2}\\25y^{2m+2} -20y^{m+1} x^{m} +4x^{2m}

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