Question

ayuden me es para mañana
resuelve y con verificacion
$x^{2} -5=69-10\\3x^{2} =27\\\sqrt{x} +4-2=10\\x^{2} -6=12+7$

Answer 1

x² - 5 = 69 - 10

x²- 5 = 59

x² = 59 + 5

x² = 64

$\sqrt{x^{2} } = \sqrt{64}$

x = +/- 8

CS = (- 8 ; 8)

3x² = 27

x² = 27/3

x² = 9

x² - 9 = 0

(x+3)(x-3) = 0

x + 3 = 0        x - 3 = 0

x = -3             x = 3

CS= (-3;3)

$\sqrt{x} + 4 -2 = 10\\\\\sqrt{x} + 2 = 10\\\\\sqrt{x} = 10 - 2\\\\\sqrt{x} = 8\\\\(\sqrt{x} )^{2} = 8^{2}\\ \\x = 64$

x² -  6 = 12 + 7

x² - 6 = 19

x² = 19 + 6

x² = 25

$\sqrt{x^{2} } = \sqrt{25}$

x = +/- 5

CS = (-5; 5)

Eternamente axllxa