Question

AYUDEN ES PARA MAÑANA doy corona y puntos por fa
$x^{2} -5=69-10\\3 x^{2} =27\\\sqrt{x} +4-2=10\\x^{2} -6=12+7$

Answer 1

Explicación paso a paso:

$x^{2} -5=69-10 \\ {x}^{2} - 5 = 59 \\ {x }^{2} = 59 + 5 \\ {x}^{2} = 64 \\ x = \sqrt{64 } \\ x = 8 \\ \\3 x^{2} =27\\ {x}^{2} = 27 \div 3 \\ {x}^{2} = 9 \\ x = \sqrt{9} \\ x = 3\\ \\ \sqrt{x} +4-2=10 \\ \sqrt{x} + 2 = 10 \\ \sqrt{x} = 10 - 2 \\ \sqrt{x } = 8 \\ x = {8}^{2} \\ x = 64 \\ \\x^{2} -6=12+7 \\ {x}^{2} - 6 = 19 \\ {x}^{2} = 19 + 6 \\ {x}^{2} = 25 \\ x = \sqrt{25} \\ x = 5$

Comprobación

x²-5=69-10

(8)²-5=69-10

64-5=69-10

59=59

3x²=27

3(3)²=27

3(9)=27

27=27

√x+4-2=10

√64+4-2=10

8+4-2=10

12-2=10

10=10

x²-6=12+7

(5)²-6=12+7

25-6=12+7

19=19

Answer 2

Respuesta:

a)

$x^{2} -5=69-10\\x^{2} =59+5\\x=\sqrt[2]{64} \\x=8$

b)

$3x^{2} =27\\x^{2} =27:3\\x=\sqrt[2]{9} \\x=3$

c)

$\sqrt{x} +4-2=10\\\sqrt{x} +4=10+2\\\sqrt{x} =12-4\\x=8^{2} \\x=64$

d)

$x^{2} -6=12+7\\x^{2} =19+6\\x=\sqrt[2]{25} \\x=5$

espero mi corazon y mi coronita , y espero que te haya ayudado y servido saludosss!!!!