Question

Hallar el promedio geométrico: 625; 16; 81; 256

Answer 1

Respuesta:

    $M_{G} = 120$

Explicación paso a paso:

$X_{1} =625 ; X_{2} = 16 ; X_{3} = 81 ; X_{4} = 256$

   N = 4

$M_{G} = \sqrt[N]{Xx_{1}* X_{2} * X_{3} * X_{4} } = \sqrt[4]{625 * 16 * 81 * 256 }$

$M_{G} = \sqrt[4]{207 360 000} = 120$

$M_{G} = 120$