Question

ayudenme porfa
(2x^4+22x^3-58x^2-x2-40) ÷ (x^2+6x-5)

Answer 1

(2x^4+22x^3-58x^2-2x-40) ÷ (x^2+6x-5) -2x^4-12x^3+10x^2 2x ^2+10x+108 ------------------------- 0 +10x^3-48x^2-2x-40 -10x^3-60x^2+50x ---------------------------------------- -108x^2+47x-40 -108x^2-648x+540 --------------------------------------- -601x+500

Answer 2

Ahí te va la solución