• Asignatura: Matemáticas
  • Autor: ruelicoar4567
  • hace 6 años

5[2x-4(3x-1)]=10x+20

Respuestas

Respuesta dada por: NayerliBerenice
3
  • 5(2x−4(3x+1))=−10x+20
  • 5(2x−4(3x+1))=−10x+20 5(2x-12x-4)=-10x+20
  • 5(2x−4(3x+1))=−10x+20 5(2x-12x-4)=-10x+205(-10x-4)= -10x+20
  • 5(2x−4(3x+1))=−10x+20 5(2x-12x-4)=-10x+205(-10x-4)= -10x+20-50x-20= -10x+20
  • 5(2x−4(3x+1))=−10x+20 5(2x-12x-4)=-10x+205(-10x-4)= -10x+20-50x-20= -10x+20-50x+10x=20+20
  • 5(2x−4(3x+1))=−10x+20 5(2x-12x-4)=-10x+205(-10x-4)= -10x+20-50x-20= -10x+20-50x+10x=20+20−40x=40
  • x= -1

Explicación paso a paso:

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