Question

halla el valor de x
$(2x - 4) \div 10 + 3 \div 4 = (6 - x) \div 5 \times 0.5$
​

Answer 1

Respuesta:

$x = \frac{5}{6}$

Espero haberte ayudado, si es así házmelo saber, gracias.

Answer 2

tarea:

halla el valor de x:

$\dfrac{\left(2x - 4\right)}{10} + \dfrac{3}{4} = \dfrac{(6-x)}{5} \cdot0,5$

Solución:

$\dfrac{\left(2x - 4\right)}{10} + \dfrac{3}{4} = \dfrac{(6-x)}{5} \cdot0,5$

→ multiplicar 10 ambos lados:

$\dfrac{\left(2x - 4\right)}{10} \cdot10+ \dfrac{3}{4} \cdot10= \dfrac{(6-x)}{5} \cdot 0,5 \cdot10$

→ simplificar:

$2x-4+\dfrac{15}{2} = -x+6$

→ restar $-4+\dfrac{15}{2}$ de ambos lados:

$2x-4+\dfrac{15}{2}-\left(-4+\dfrac{15}{2} \right) = -x+6 - \left(-4 + \dfrac{15}{2} \right)$

→ simplificar:

$2x = -x + \dfrac{5}{2}$

→ sumo 'x' ambos lados:

$2x + x= -x + \dfrac{5}{2} + x$

→ simplificar:

$3x=\dfrac{5}{2}$

→ dividir ambos lados entre 3:

$\dfrac{3x}{3} = \dfrac{\dfrac{5}{2} }{3}$

→ y simplificar:

$\boxed{x=\dfrac{5}{6} }$

y listo la respuesta de la ecuación es cinco sexto: 5/ 6

Comprobamos:

$\dfrac{\left(2x - 4\right)}{10} + \dfrac{3}{4} = \dfrac{(6-x)}{5} \cdot0,5$

$\dfrac{\left(2\left(\dfrac{5}{6} \right)- 4\right)}{10} + \dfrac{3}{4} = \dfrac{\left(6-\left(\dfrac{5}{6}\right)\right)}{5} \cdot0,5$

$\dfrac{\left(\left(\dfrac{2}{1} \cdot\dfrac{5}{6}\right) - 4\right)}{10} + \dfrac{3}{4} = \dfrac{\left(-\dfrac{5}{6}+6\right)}{5} \cdot0,5$

$\dfrac{\left(\dfrac{5}{3} - 4\right)}{10} + \dfrac{3}{4} = \dfrac{\left(-\dfrac{5}{6}+\dfrac{6\cdot6}{6} \right)}{5} \cdot0,5$

$\dfrac{\left(\dfrac{5}{3} - \dfrac{4\cdot3}{3} \right)}{10} + \dfrac{3}{4} = \dfrac{\left(\dfrac{-5+6\cdot6}{6} \right)}{5} \cdot0,5$

$\dfrac{\left(\dfrac{5-4\cdot3}{3}\right)}{10} + \dfrac{3}{4} = \dfrac{\left(\dfrac{31}{6} \right)}{5} \cdot0,5$

$\dfrac{\left(-\dfrac{7}{3\right)} }{10} + \dfrac{3}{4} = \dfrac{31}{5\cdot6} \cdot0,5$

$\dfrac{-7}{10\cdot3} + \dfrac{3}{4} = \dfrac{31}{30} \cdot0,5$

$\dfrac{-7}{30} + \dfrac{3}{4} = \dfrac{31}{30} \cdot\dfrac{1}{2}$

$-\dfrac{14}{60} + \dfrac{45}{60} = \dfrac{31}{30} \cdot\dfrac{1}{2}$

$\dfrac{-14+45}{60} = \dfrac{31\cdot1}{30\cdot2}$

$\boxed{\dfrac{31}{60} = \dfrac{31}{60}}$