Question

1/x-3 +1 = 1/x - 3 resolver:

Answer 1

1/(x-3) - 1/x = -3 -1

(x - (x-3))/((x)(x-3)) = -4

(x-x+3)/(x^2-3x) = -4

3 = -4(x^2-3x)

3= -4x^2+12x

4x^2 -12x +3= 0

Ax^2+Bx+C=0 ==>. ∆ = B^2-4AC

si: ∆ > 0 (soluciones reales conjugadas).

∆=(-12)^2-4(4)(3)= 96 >0 (sol. real conjug.)

x= [-(-12) +- √∆]/(2.4)

x = (12 +- √96)/8 = (12+-4√6)/8 = (3+-√6)/2

x1= (3+√6)/2. x2= (3-√6)/2