Question

$\frac{ \times + 3}{10} = 10 \\ \\ \\ \frac{20}{ \times } = 4 \\ \\ \\ 12 \times - 18 = 6 \times \\ \\ \\ 4( \times - 31) = 0 \\ \\ \\ 50 - 2 \times = \times + 11 \\ \\ \\ 3( \times + 3) = 7 \times - 11 \\ \\ \\ \frac{50}{ \times + 3} = 10 \\ \\ \\ \frac{42}{ \times } = 3 \\ \\ \\ 5(x - 5) = 7 \times - 41 \\ \\ \\ \sqrt{ \times + 2} = 3 \\ \\ \\ \frac{51}{ \times } = 3 \\ \\ \\ 3 \times ( \times - 21) = \times - 17 \\ \\ \\ \ \ \ \frac{ {x}^{2} - 22}{3} = 33 \\ \\ \\ { \times }^{8} - 200 = 56 \\ \\ \\ { \times }^{4 } + 12 = 93 \\ \\ \\ 4 { \times }^{2} + 3 = 103 \\ \\ \\ 4 { \times }^{2} = 196 \\ \\ \\ 90 - 3 \times = 6 \times + 27 \\ \\ \\ \\ ecuciones\: azcen \: si \: puedes \: y \: tienes \: tiempo \: m \: ayudas \:$
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Answer 1

Creo que es así:

$a) \: \frac{x + 3}{10} = 10$

$x + 3 = 10 \times 10$

$x + 3 = 100$

$x = 100 - 3$

$x = 97$

$b) \: \frac{20}{x} = 4$

$20 = 4x$

$4x = 20$

$x = \frac{20}{4}$

$x = 5$

$c) \: 12x - 18 = 6x$

$12x - 6x = 18$

$6x = 18$

$x = \frac{18}{6}$

$x = 3$

$d) \: 4(x - 31) = 0$

$4x - 124 = 0$

$4x = 124$

$x = 31$

$e) \: 50 - 2x = x + 11$

$- 2x - x = 11 - 50$

$- 3x = - 39$

$3x = 39$

$x = \frac{39}{3}$

$x = 13$

$f) \: 3(x + 3) = 7x - 11$

$3x + 9 = 7x - 11$

$3x - 7x = - 11 - 9$

$- 4x = - 20$

$4x = 20$

$x = \frac{20}{4}$

$x = 5$

$g) \: \frac{50}{x + 3} = 10$

$50 = 10(x + 3)$

$50 = 10x + 30$

$- 10x = 30 - 50$

$- 10x = - 20$

$10x = 20$

$x = \frac{20}{10}$

$x = 2$

$h) \: \frac{42}{x} = 3$

$42 = 3x$

$3x = 42$

$x = \frac{42}{3}$

$x = 14$

$i) \: 5(x - 5) = 7x - 41$

$5x - 25 = 7x - 41$

$5x - 7x = - 41 + 25$

$- 2x = - 16$

$2x = 16$

$x = \frac{16}{2}$

$x = 8$

$j) \: \sqrt{x + 2} = 3$

$x + 2 = {3}^{2}$

$x + 2 = 9$

$x = 9 - 2$

$x = 7$

$k) \: \frac{51}{x} = 3$

$51 = 3x$

$3x = 51$

$x = \frac{51}{3}$

$x = 17$

$l) \: \frac{ {x}^{2} - 22 }{3} = 33$

${x}^{2} - 22 = 33 \times 3$

${x}^{2} - 22 = 99$

${x}^{2} = 121$

$x = \sqrt{121}$

$x = 11$

$m) \: {x}^{8} - 200 = 56$

${x}^{8} = 56 + 200$

${x}^{8} = 256$

$x = \sqrt[8]{256}$

$x = 2$

$n) \: {x}^{4} + 12 = 93$

${x}^{4} = 93 - 12$

${x}^{4} = 81$

$x = \sqrt[4]{81}$

$x = 3$

$o) \: 4 {x}^{2} + 3 = 103$

$4 {x}^{2} = 103 - 3$

$4 {x}^{2} = 100$

${x}^{2} = \frac{100}{4}$

${x}^{2} = 25$

$x = \sqrt{25}$

$x = 5$

$o) \: 4 {x}^{2} = 196$

${x}^{2} = \frac{196}{4}$

${x}^{2} = 49$

$x = \sqrt{49}$

$x = 7$

$p) \: 90 - 3x = 6x + 27$

$- 3x - 6x = 27 - 90$

$- 9x = - 63$

$9x = 63$

$x = \frac{63}{9}$

$x = 7$

Espero haber ayudado.

(Creo que eso es todo, no estoy segura)