Question

consigna: resolver los siguientes ecuaciones
${2x}^{2} + 1 = 19$
${x}^{4} - 7 = 74$

$\sqrt{x - 3 = 6}$
ayudenme porfa
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Answer 1

Respuesta:

${2x}^{2} + 1 = 19 \\ {2x}^{2} = 19 - 1 \\ {2x }^{2} = 18 \\ {x}^{2} = \frac{18}{2} \\ {x}^{2} = 9 \\ \sqrt{ {x}^{2} } = \sqrt{9} \\ x = 3 \\ </p><p> {x}^{4} - 7 = 74 \\ {x}^{4} = 74 + 7 \\ {x}^{4} = 81 \\ \sqrt[4]{ {x}^{4} } = \sqrt[4]{81} \\ x = 3 \\ </p><p>\sqrt{x - 3 = 6} \\ </p><p> \sqrt{x = 6 + 3} \\ \sqrt{x = 9} \\ \sqrt{x} = 3 \\ {( \sqrt{x} )}^{2} = {(3)}^{2} \\ x = 9 \\ espero \: que \: te \: sirva....</p><p>$