Question

(12x^4 y^5)/(6x^3 y^2 )÷(2x^6 y)/(4xy^7 )
Ayudenme doy corona

Answer 1

Respuesta:

$= \frac{4 {y}^{9}}{ {x}^{4} } = 4 {x}^{ - 4} {y}^{9}$

Explicación paso a paso:

$\frac{12 {x}^{4} {y}^{5}}{6 {x}^{3} {y}^{2} } \div \frac{2 {x}^{6}y }{4x {y}^{7} } = \frac{(12 {x}^{4} {y}^{5})(4x {y}^{7} )}{(6 {x}^{3} {y}^{2} )(2 {x}^{6}y) } = \frac{48 {x}^{5} {y}^{12} }{12 {x}^{9} {y}^{3} } = \frac{4 {y}^{9}}{ {x}^{4} } = 4 {x}^{ - 4 } {y}^{9}$