Question

2 ejempos de suma, resta, multiplicacion, divison, potenciacion y radicacion de numeros racionales

Answer 1

Saludos

Suma
$\frac{2}{3} + \frac{8}{3} = \frac{10}{3}$
$\frac{2}{5} + \frac{8}{4} = \frac{8}{20}+ \frac{40}{20} = \frac{48}{20} = \frac{12}{5}$
Resta
$\frac{2}{3} + \frac{8}{3} = \frac{10}{3}$
$\frac{2}{5} + \frac{8}{4} = \frac{8}{20}+ \frac{40}{20} = \frac{48}{20} = \frac{12}{5}$
Multiplicación
$\frac{-2}{3} ( \frac{4}{9}) =( \frac{-2*4}{3*9} ) = \frac{-8}{27}$
$\frac{-1}{8} ( \frac{-3}{5}) =( \frac{-1(-3)}{8*5} ) =\frac{3}{40}$
División
$\frac{ \frac{2}{3} }{ \frac{1}{5} } = \frac{2*5}{3*1} = \frac{10}{3}$
$\frac{ \frac{-4}{7} }{ \frac{-3}{7} } = \frac{-4(7)}{-3(7)} = \frac{-4}{-3} = \frac{4}{3}$
Potenciación
$( \frac{2}{5}) ^{3} = \frac{ 2^{3} }{ 5^{3} } = \frac{8}{125}$
$( \frac{2}{5}) ^{3} = \frac{ 2^{3} }{ 5^{3} } = \frac{8}{125}$
Radicación
$\sqrt{ \frac{4}{9} } = \frac{ \sqrt{4} }{ \sqrt{9} } = \frac{2}{3}$
$\sqrt[3]{ \frac{-8}{-27} } = \frac{ \sqrt[3]{-8} }{ \sqrt[3]{-27} } = \frac{-2}{-3} = \frac{2}{3}$

Espero te sirva