Question

\frac{2}{3}m^2+\frac{1}{2}m^2n-\frac{\:5}{6}mn^2-\frac{1}{9}n^3por\frac{3}{4}m^2n^3

Answer 1

Respuesta:

Explica

Mostrar pasos

$\frac{2}{3}m^2=\frac{2m^2}{3}$

Mostrar pasos

$\frac{1}{2}m^2n=\frac{m^2n}{2}$

Mostrar pasos

$\frac{5}{6}mn^2=\frac{5mn^2}{6}$

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$\frac{1}{9}n^3por\frac{3}{4}m^2n^3=\frac{m^2n^6por}{12}$

$=\frac{2m^2}{3}+\frac{m^2n}{2}-\frac{5mn^2}{6}-\frac{m^2n^6por}{12}$ción paso a paso: