Question

(x - 2)(3x + 5) = (x - 2)(x + 2)

Answer 1

(x - 2) (3 x + 5) = (x - 2) (x + 2)

(x - 2) (3 x + 5) = (x) (3 x) + (x) (5) + (-2) (3 x) + (-2) (5) = 3 x^2 + 5 x - 6 x - 10 = 3 x^2 - x - 10:

3 x^2 - x - 10 = (x - 2) (x + 2)

(x - 2) (x + 2) = (x) (x) + (x) (2) + (-2) (x) + (-2) (2) = x^2 + 2 x - 2 x - 4 = x^2 - 4:

3 x^2 - x - 10 = x^2 - 4

Subtract x^2 - 4 from both sides of 3 x^2 - x - 10 = x^2 - 4:

-x^2 - 4 + 3 x^2 - x - 10 = (x^2 - 4) - x^2 - 4

(x^2 - 4) - (x^2 - 4) = 0:

-(x^2 - 4) + 3 x^2 - x - 10 = 0

-(x^2 - 4) = -(-4) - x^2:

-(-4) - x^2 + 3 x^2 - x - 10 = 0

-(-4) = 4:

3 x^2 - x^2 - x - 10 + 4 = 0

3 x^2 - x^2 - x - 10 + 4 = (3 x^2 - x^2) - x + (-10 + 4):

(3 x^2 - x^2) - x + (-10 + 4) = 0

3 x^2 - x^2 = 2 x^2:

2 x^2 - x + (-10 + 4) = 0

4 - 10 = -6:

Answer:

| 2 x^2 - x + -6 = 0