Question

3(x+2)(x-2)=(x-4)²+8​

Answer 1

Respuesta:

3(x+2)(x-2)=(x-4)²+8

3( x² - 4) = x² - 8x + 16 +8

3x² - 12 = x²- 8x + 16 +8

3x² - x2+ 8x= 16 +8 + 12

2x²+8x= 36

2x²/2 +8x/2 =36/2

x²+ 4x = 18

x²+ 4x - 18 =0

Aplicamos la formula general

a=1

B= 4

C= - 18

$\frac{ - ({b})± \sqrt{ {b}^{2}- 4(a)(c) } }{2(a)}$

$\frac{ - (4 )± \sqrt{4 ^{2} - 4(1)( - 18)} }{2(1)}$

$\frac{ - 4± \sqrt{16 + 72} }{2}$

$\frac{ - 4 ± \sqrt{88} }{2}$

$x = { - 2± \sqrt{88} }$