Question

A. 2x + 9 = 4x + 3 B. 5x – 1 = –x + 5 + 4x C. 3x + 5 = –x + 5 + 4x D. 2x + 3 = 1 + 2x – 5 E. 7x – 3 = 3x + 9 F. 3x = 10 G. 12 – 6x + 4 = 1 – x + 3 H. 3x + 9 = x – 5 I. 2x – 4x = 27 – 2 – 16 J. 9x – 18 = 8x ayudaaaaa le doy corona al que la conteste completa

Answer 1

Respuesta:

1 Resuelve las siguientes ecuaciones:

a) (4x + 3)(4x – 3) – 4(3 – 2x)

2 = 3x b) 2x + 3(x – 4)2 = 37 + (x – 3)(x + 3)

c) x + 3

5 – (x – 1)2

4 = 5

4 x – (

x + 2

2 )

2

d) (x – 1)(x + 2)

12 – x – 3

3

= 1 + (x + 1)(x – 2)

6

a) 16x 2 – 9 – 4(9 + 4x 2 – 12x) = 3x

16x 2 – 9 – 36 – 16x 2 + 48x = 3x 8 48x – 3x = 45 8 45x = 45 8 x = 1

Solución: x = 1

b) 2x + 3(x 2 – 8x + 16) = 37 + x 2 – 9

2x + 3x 2 – 24x + 48 = 28 + x 2 8 2x 2 – 22x + 20 = 0

x 2 – 11x + 10 = 0 8 x = 11 ± 9

2 = 10

1

Soluciones: x1 = 10, x2 = 1

c) x + 3

5 – x

2 – 2x + 1

4 = 5x

4 – x

2 + 4x + 4

4

4x + 12 – 5x 2 + 10x – 5 = 25x – 5x 2 – 20x – 20

9x + 27 = 0 8 x = –3

Solución: x = –3

d) (x – 1)(x + 2) – 4(x – 3) = 12 + 2(x + 1)(x – 2)

x 2 + x – 2 – 4x + 12 = 12 + 2x 2 – 2x – 4

x 2 + x – 2 = 0 8 x = –1 ± 3

2 = 1

–2

Soluciones: x1 = 1, x2 = –2

2 Comprueba que las ecuaciones siguientes son de 2.º grado incompletas. Resuélvelas sin aplicar la fórmula general.

a) x + 7

12 – x

2 + 1

4 = 1 – x

2 + 2

3 b) (x + 1)2 – (x – 2)2 = (x + 3)2 + x2 – 20

c) x (x – 2)

4 – x + 1

6 = x – 3

2 – x – 4

3 d) x (

x +

1

2)

– x – 2

2

+

x

2 – 1

3

= 0

a) x + 7 – 3(x 2 + 1) = 12 – 4(x 2 + 2)

x + 7 – 3x 2 – 3 = 12 – 4x 2 – 8

x 2 + x = 0 8 x(x + 1) = 0 8 x = 0; x = –1

Soluciones: x1 = 0, x2 = –1

b) x 2 + 2x + 1 – x 2 + 4x – 4 = x 2 + 6x + 9 + x 2 – 20

2x 2 – 8 = 0 8 x 2 = 4 8 x = 2; x = –2

Soluciones: x1 = 2, x2 = –2

Explicación paso a paso: