Question

Resolver el siguiente sistema de ecuaciones: (Por Cramer) 3X - 2Y = -16 5X +6Y = 20

Answer 1

Respuesta:

$X= \frac{|Mx|}{M}=\frac{-56}{8}= -7\\ \\Y=\frac{|My|}{M}=\frac{140}{8}= 17.5$

Explicación paso a paso:

$M=\left[\begin{array}{ccc}3&2\\5&6\\\end{array}\right]= (Se multiplica cruzado)= |M|= (3)(6)-(2)(5)=\\ |M|= 18-10=8$

$Mx=\left[\begin{array}{ccc}-16&-2\\20&6\\\end{array}\right] = (Se multiplica cruzado) = |Mx|=(-16)(6)- (-2)(20)=\\ |Mx|= -96 +40= -56$

$My=\left[\begin{array}{ccc}3&-16\\5&20\\\end{array}\right]= (Se multiplica cruzado)= |My|= (3)(20) - (-16)(5)=\\ |My|=60 + 80= 140$