Question

Por identidades trigonometricas


(secx+1)/tanx=tanx/(secx-1)

Answer 1

$\begin{matrix} \dfrac{\sec{x}+1}{\tan{x}}&=&\dfrac{\tan{x}}{\sec{x}-1} \\ \\ &=& \left(\dfrac{\tan{x}}{\sec{x}-1}\right) \ \cdot \left( \dfrac{\sec{x}+1}{\sec{x}+1} \ \right) \\ \\ &=& \dfrac{\tan{x}(\sec{x}+1)}{\sec^2{x}-1} \\\\ &=& \dfrac{\tan{x}(\sec{x}+1)}{\tan^2(x)} \\\\ &=& \dfrac{\sec{x}+1}{\tan{x}} \end{matrix}$