Question

ayuden me, lo necesito ahorita :(!!!!

Answer 1

(2ax+4bx)/(3ay+6by)=2x(a+2b)/3y(a+2b)=2x/3y

(x²-x-20)/(x²-x-30)=(x-5)(x+4)/(x-6)(x+5)=x+4/x-6

Answer 2

$\frac{2ax+4bx}{3ay+6by} = \frac{2x(a+2b)}{3y(a+2b)} = \frac{2x}{3y}$

$\frac{ x^{2} -x-20}{ x^{2} +x-30} = \frac{(x+4)(x-5)}{(x+6)(x-5)} = \frac{x+4}{x+6}$