Question

Resuelve la ecuación: 5x²+3x=2

Answer 1

$5 x^{2} +3x = 2$

$5x^{2} +3x -2 = 0$

5x              -2
x               +1

5x - 2x = 3x

(5x - 2)(x+1) = 0

5x - 2 = 0          x + 1 = 0

5x = 2               x = -1

x = 2/5              x = - 1

CS= (-1; 2/5) 

Answer 2

$5x^2+3x=2 \qquad pasas \ el\ 2 \ restando \ e \ igualas\ a \ cero\ la \ ecuaci\'on \\ \\ 5x^2+3x-2=0 \\ \\ aplicas\ Bhaskara\to \frac{-b\pm \sqrt{b^2-4ac} }{2a}\quad a= 5\quad b=3\quad c=-2 \\ \\ x_{1\ y\ 2}= \frac{-3\pm \sqrt{3^2-4(5)(-2)} }{2(5)}\\ \\ x_{1\ y\ 2}= \frac{-3\pm \sqrt{9+40} }{10} \\ \\ x_{1\ y\ 2}= \frac{-3\pm \sqrt{49} }{10}\\ \\ x_{1\ y\ 2}= \frac{-3\pm 7 }{10} \\ \\ x_1=\frac{-3+ 7 }{10} \qquad\qquad x_2=\frac{-3-7 }{10}$

$x_1=\frac{4 }{10} \qquad\qquad x_2=\frac{-10 }{10} \\ \\ x_1=\frac{3 }{5} \qquad\qquad x_2=-1 \\ \\ Soluci\'on \qquad 5x^2+3x-2=0\to (x- \frac{2}{5})(x+1)$

Espero que te sirva, salu2!!!!