Question

1)hallar x:
 $x^{2}$-5x+6=0

2)hallar x:
$\frac{ x^{2} -1}{x+1}$ +x=5

Answer 1

Espero haber podido ayudarte :)

Answer 2

$x^{2} -5x+6= 0$

x            -3
x            -2

(x-3)(x-2)= 0

x-3 = 0       x -2 = 0
x = 3          x = 2

cs= (2;3)

$\frac{ x^{2} -1}{x+1} +x = 5$

$\frac{(x+1)(x-1)}{x+1} + x = 5$

x-1 + x = 5

2x = 5+1
2x = 6
x = 6/2
x = 3