Question

Como se resuelven estas ecuaciones:(1) 12.(X-3)=6.(X+2) (2): 3√2X+8+2=3.2 (3): 2X+8+2=3.2 5.(2x-3)= 20+3X (4): (X+3)pot2+29=15pot2 "pot" es potenciado

Answer 1

Respuesta:

(1) 12.(X-3)=6.(X+2)

12 x - 36 = 6x + 12

12 x - 6 x = 12 + 36

6x = 48

x = 8

(2): 3√2X+8+2=3.2

3√2X+10 = 6

3√2X = 6 - 10

3√2X = - 4

√2X = - 4 / 3

x = (-4/3) / (√2/1)

x = -4 / 3√2

x = -4 / 3√2 * √2/√2 = -4√2 / 6 = -2√2 / 3

(3): 2X+8+2=3.2 5.(2x-3)= 20+3X

2x + 8 + 2 = 6 ( 10 x - 15)

(4): (X+3)pot2+29=15pot2

(x + 3) (x + 3) + 29 = 15*15

xpot2 + 3 x + 3x + 9 + 29 = 225

xpot2 + 6x + 9 = 196

x pot 2 + 6x = 187

x (x + 6) = 187

x = 187

x + 6 = 187

x = 181

X tiene valores: 187 y 181