Question

resuelva los Siguientes ejercicios planteados
(×+4)(×+10)

(z²+11)(z²+1)

(2y²+8)(2y²-6)

(-2-y)(-9-y)​

Answer 1

Respuesta:

hola

Explicación paso a paso:

(×+4)(×+10)

x+4=x+10

2x=10-4

2x=6

x=3

(z²+11)(z²+1)

$z²+11 = z²+1$

$2 {z}^{2} = 1 - 11$

$2 {z}^{2} = 10$

${z}^{2} = 10sobre \: 2$

${z}^{2} = 5$

(2y²+8)(2y²-6)

$2y²+8 = 2y²-6$

$4 {y}^{2} = - 6 - 8$

$4 {y}^{2} = 14$

${y}^{2} = 7$

(-2-y)(-9-y)

$-2-y = -9-y$

$2y = - 9 + 2$

$2y = 7$

$y = 3.5$