Question

2^6 - ( 4^2 + 2^5 ) + 3 ( 2^(3 )- 2^2 ) - 2^0
plis me ayudan

Answer 1

2⁶−(4²+2⁵)+3(2³−2²)−2⁰

=64−(4²+2⁵)+3(2³−2²)−2⁰

=64−(16+2⁵)+3(2³−2²)−2⁰

=64−(16+32)+3(2³−2²)−2⁰

=64−48+3(2³−2²)−2⁰

=16+3(2³−2²)−2⁰

=16+3(8−2²)−2⁰

=16+3(8−4)−2⁰

=16+(3)(4)−2⁰

=16+12−2⁰

=28−2⁰

=28−1

=27