Question

Hola Quien me ayuda con esto Producto de binomios con un termino comun a) (X + 9) (X + 5) = b) (X – 8) (X + 2) = c) (X – 7) (X + 10) = d) (X – 12) (X – 5) = e) (5Y – 3) (5Y – 2) =

Answer 1

Respuesta:

a) (X + 9) (X + 5)= X^2 + 14X + 45

b) (X – 8) (X + 2) = X^2 - 6X - 16

c) (X – 7) (X + 10) = X^2 + 3X - 70

d) (X – 12) (X – 5) = X^2 - 17X + 60

e) (5Y – 3) (5Y – 2) = 25Y^2 - 5X +6

Explicación paso a paso:

a) (X + 9) (X + 5)=

X^2 + (9+5)X + 9(5)

X^2 + 14X + 45

b) (X – 8) (X + 2) =

X^2 + (-8+2)X + (-8)(2)

X^2 - 6X - 16

c) (X – 7) (X + 10) =

X^2 + (-7+10)X + (-7)(10)

X^2 + 3X - 70

d) (X – 12) (X – 5) =

X^2 + (-12-5)X + (-12)(-5)

X^2 - 17X + 60

e) (5Y – 3) (5Y – 2) =

25Y^2 + (-3-2)X + (-3)(-2)

25Y^2 - 5X +6