Question

P(x)=x2+1

P(1)=

P(3)=

P(-2)=

P(-10)=

Answer 1

$p(x) = {x}^{2} + 1 \\ \\ p(1) = {(1)}^{2} + 1 = 1 + 1 = 2 \\ \\ p(3) = {(3)}^{2} + 1 = 9 + 1 = 10 \\ \\ p( - 2) = {( - 2)}^{2} + 1 = 4 + 1 = 5 \\ \\ p( - 10) = {( - 10)}^{2} + 1 = 100 + 1 = 101$

espero haberte ayudado