Question

(2/3X2Y+5/4XY2-2/5Y3)+(4/9X2Y-2/3XY2+8/9Y3+6

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Answer 1

Respuesta:

$\frac{305xy+132y}{90}+6$

Explicación paso a paso:

$\left(\frac{2}{3}x\cdot \:2y+\frac{5}{4}xy\cdot \:2-\frac{2}{5}y\cdot \:3\right)+\left(\frac{4}{9}x\cdot \:2y-\frac{2}{3}xy\cdot \:2+\frac{8}{9}y\cdot \:3+6\right)$

$\frac{2}{3}x\cdot \:2y+\frac{5}{4}xy\cdot \:2-\frac{2}{5}y\cdot \:3+\frac{4}{9}x\cdot \:2y-\frac{2}{3}xy\cdot \:2+\frac{8}{9}y\cdot \:3+6$

$2\cdot \frac{5}{4}xy-3\cdot \frac{2}{5}y+2\cdot \frac{4}{9}xy+3\cdot \frac{8}{9}y+6$

$\frac{5}{4}xy\cdot \:2 =\frac{5xy}{2}$

$\frac{2}{5}y\cdot \:3=\frac{6y}{5}$

$\frac{4}{9}x\cdot \:2y=\frac{8xy}{9}$

$\frac{8}{9}y\cdot \:3=\frac{8y}{3}$

$\frac{5xy}{2}-\frac{6y}{5}+\frac{8xy}{9}+\frac{8y}{3}+6$

$\frac{305xy+132y}{90}+6$

(Espero que te haya servido de ayuda)