Question

Resolver ecuaciones
a)4.(3x+2)=5x+6
b)(10x+20).(-5x+2)=0
c)25x(al cuadrado)-100=0

Answer 1

a)

$4(3x + 2) = 5x + 6$
$12x + 8 = 5x + 6$
$7x = -2$
$x = \frac{-2}{7}$

b)
$(10x + 20)(-5x + 2) = 0$
Aqui hay dos soluciones:
- Primera solucion:
$10x + 20 = 0$
$10x = -20$
$x= \frac{-20}{10}$
$x = -2$

- Segunda solución:
$-5x + 2 = 0$
$5x = 2$
$x = \frac{2}{5}$

c)
$25 x^{2} - 100 = 0$
$25 x^{2} = 100$
$x^{2} = 4$
$x = 2$