Question

a+b=6 ab=5 hallar a-b

Answer 1

Respuesta:

$(a+b)^{2} =a^{2} +2ab+b^{2}$

$(6)^{2} =a^{2} +2(5)+b^{2}$

$36 -10=a^{2} +b^{2}$

$26=a^{2} +b^{2}$

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$(a-b)^{2} =a^{2} -2ab+b^{2}$

$(a-b)^{2} =a^{2}+b^{2} -2ab$

$(a-b)^{2} =26-2(5)$

$(a-b)^{2} =26-10$

$(a-b)^{2} =16$

$a-b=\sqrt{16}$

$a-b=4$