Question

56-C7 (9 pag.89) Resuelve. a) [(–2)4 · (–2)6 ] : (+2)8 = b) [(+3)4 · (–3)3 ] : (–3)6 = c) (+5)8 : [(–5)2 · (–5)4 ] = d) (–7)7 : [(–7)4 · (–7)3 ] =

Answer 1

Respuesta:

coronaa

Explicación paso a paso:

a) [(–2)4 · (–2)6 ] : (+2)8 =

$\frac{(-2)^{4+6} }{(+2)^{8} }= \frac{(-2)^{10} }{(+2)^{8} } =(-2)^{10-8} =(-2)^{2}=4$

b) [(+3)4 · (–3)3 ] : (–3)6 =

$\frac{(-3)^{4+3}}{(-3)^{6} }= \frac{(-3)^{7} }{(-3)^{6} } =(-3)^{7-6} =(-3)^{1}=-3$

c) (+5)8 : [(–5)2 · (–5)4 ] =

$\frac{(+5)^{8}}{(-5)^{2+4} }= \frac{(+5)^{8} }{(-5)^{6} } =(-5)^{8-6} =(-5)^{2}=25$

d) (–7)7 : [(–7)4 · (–7)3 ] =

$\frac{(-7)^{7}}{(-7)^{4+3} }= \frac{(-7)^{7} }{(-7)^{7} } =1$