Question

(Y+4)^2=11 ayuda por favor

Answer 1

 (y + 4)² = 11

⇔ y² + 8y + 16 = 11

⇔ y² + 8y + 16 - 11 = 0

⇔y² + 8y + 5 = 0

a = 1 ; b = 8 y c = 5

Δ = b² - 4ac = 8² - 4 × 1 × 5 = 64 - 20 = 44 > 0

x₁ = (-b - √Δ)/2a = ( -8 - 2√11)/2 = -4 -√11

x₂ = (-b + √Δ)/2a = (-8 + 2√11)/2 = -4 + √11

S = {-4-√11 ; -4 + √11}