Question

3 + 2x [al cuadrado] - 3x = 7 + 6x, hallar e producto de raíces

Answer 1

Respuesta:

$x_{1} =\frac{9+\sqrt{(113) } }{4} = 4.907536453$

$x_{2} =\frac{9-\sqrt{(113) } }{4}=-0.4075364532$

Explicación paso a paso:

$3+2x^{2}-3x=7+6x$

$2x^{2} -3x-6x=7-3$

$2x^{2} -9x=4$

$2x^{2}-9x-4 =0$

Formula General

$x_{1} =\frac{-b+\sqrt{b^{2} -4ac} }{2a}$

$x_{2} =\frac{-b-\sqrt{b^{2} -4ac} }{2a}$

a= 2

b= -9

c= -4

$x_{1} =\frac{-(-9)+\sqrt{(-9^{2})-4(2)(-4) } }{2(2)}$

$x_{2} =\frac{-(-9)-\sqrt{(-9^{2})-4(2)(-4) } }{2(2)}$

$x_{1} =\frac{9+\sqrt{(113) } }{4}$

$x_{2} =\frac{9-\sqrt{(113) } }{4}$