Question

Cuánto da (a²+3a+2)÷(a+1)=

(6x²+16x+8)÷(3x+2)=

(6a²+a-2)÷(2a-1)=

(4x²-36)÷(2x-6)=

(3y⁵+2y²-12y-4)÷(y²-2)= Porfa ayuda.

Answer 1

(a²+3a+2)÷(a+1)

= a²+3a+2

a+1

= a²+2a+a+2

a+1

= a×(a+2)+a+2

a+1

= (a+2) × (a+1)

a+1

= a+2

(6x²+16x+8)÷(3×+2)

=(6x²+16x+8)÷6

= 6x²+16x+8

6

= 2(3x²+8x+4)

6

= 3x²+8x+4

3

(6a²+a-2)÷(2a-1)

= 6a²+a-2

2a-1

= 6a²+4a-3a-2

2a-1

= 2a×(3a+2)-(3a+2)

2a-1

= (3a+2)×(2a-1)

2a-1

= 3a+2

(4x²-36)÷(2x-6)

= (4x²-36)÷(-12)

= 4x²- 36

-12

= 4(x²-9)

-12

= x2-9

-3

= 9-x²

3

(3y⁵+2y²-12y-4)÷(y²-2)

= 3y⁵+2y²-12y-4

y² - 2