Question

Calcular “ b ” si: tg ( 2b -30°) .ctg(b + 50º) = 1

Answer 1

Respuesta:

80

Explicación paso a paso:

Si

tgα.ctgβ = 1

tgα = 1/ctgβ = tgβ

tgα = tgβ

α = β

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tg(2b - 30°) .ctg(b + 50º) = 1

tg(2b - 30°) = 1/ctg(b + 50)

tg(2b - 30) = tg(b + 50)

∴ 2b - 30 = b + 50

2b - b = 50 + 30

b = 80