Question

Halla el grado absoluto, y grado relativo con respecto a la variable x 6x^5y^2 + 3x^4y-8x^3 +1

Answer 1

Explicación:

$216 {. { = + \times 0 {9x5y \div \div < \div \times - + \frac{2 \frac{ \times \frac{ = \sqrt{ > \sqrt{ = \frac{3kjl ln(ee\pi \alpha \% log( log_{ ln( \binom{\pi \cot( \cot(?) ) }{?} ) }(?) ) ) { \sqrt{ \sqrt[ { | > \leqslant \geqslant < { \\ \times - \frac{ \div x { - { + ( \times \frac{ \frac{x1 {93 { {?}^{2} }^{?} }^{?} }{?} }{?} }^{2} }^{?} }{?} }^{2} | }^{?} \times \frac{?}{?} ]{?} } }^{2} }{?} } } }{?} }{?} }{?} }^{?} }^{2} }^{2}$