Question

Hallar "x+y"
$\sqrt{x} - 2 \sqrt{y} = \sqrt{x + y}$
$y - x = 0.7$

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Answer 1

Respuesta:

Explicación paso a paso:

$(\sqrt{x}-2\sqrt{y} )^{2} =(\sqrt{x+y} )^{2} \\x-4\sqrt{xy} + 4y = x+y\\9y=16x\\\frac{x}{y}=\frac{9k}{16k}\\ 16k-9k= 0.7\\k =1/10\\ 16/10 + 9/10 = 25/10 = 5/2 = 2.5$