Question

13. Si: p Δ q = p+2q; hallar "x" en:
(6 Δ 3) Δ 6 = (x+2) Δ (x - 2)

Answer 1

Si.
(p Δ q ) = p + 2q

(6 Δ 3 ) Δ 6 = (x + 2) Δ (x - 2)
(6 + 2(3)) Δ 6 = (x + 2) + 2(x - 2)
(6 + 6) Δ 6 = x + 2 + 2x - 4
12 Δ 6 = 3x - 2
(12 + 2 *6) = 3x - 2
12 + 12 = 3x - 2
24 = 3x - 2
24 + 2 = 3x
26/3 = x

Respuesta.
x = 26/3