Question

matematicas interpolar 10 medios aritmeticos entre 4 y 48

Answer 1

Tenemos.

d = diferencia
a1 = primer termino = 4
an = ultimo termino = 48
n = numero de terminos = 10 + 2 = 12

Formula .

d = (an - a1)/ (n + 1)
d = (48 - 4)/(12 - 1)
d = 44/11
d = 4

1er termino =   4
2do termino =  4 + d = 4 + 4 = 8
3er termino =  8 + d = 8 + 4 = 12
4to termino = 12 + d = 12 + 4 = 16
5to termino = 16 + d = 16 + 4 = 20
6to termino =  20 + d = 20 + 4 = 24
7mo termino=  24 + d = 24 + 4 = 28
8vo termino=   28 + d =  28 + 4 = 32
9no termino =  32 + d = 32 + 4 = 36
10mo termino =36 +d = 36 + 4 = 40
11avo termino = 40 + d = 40 + 4 = 44
12avo termino = 44 + d = 44 + 4 = 48

Respuesta.
4. 8 . 12 . 16 . 20 . 24 . 28 . 32 . 36 . 40 . 44 . 48