Question

(4x+1)2 + (4x-3)2 - 16x(2x-1) productos notables

Answer 1

Respuesta:

10

Explicación paso a paso:

$\left(4x+1\right)^2+\left(4x-3\right)^2-16x\left(2x-1\right)$

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• $\left(4x+1\right)^2$

$=\left(4x\right)^2+2\cdot \:4x\cdot \:1+1^2\\=16x^2+8x+1$

• $\left(4x-3\right)^2$

$=\left(4x\right)^2-2\cdot \:4x\cdot \:3+3^2\\=16x^2-24x+9$

• $-16x\left(2x-1\right)$

$=-16x\cdot \:2x-\left(-16x\right)\cdot \:1\\=-16\cdot \:2xx+16\cdot \:1\cdot \:x\\=-32x^2+16x$

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$=16x^2+8x+1+16x^2-24x+9-32x^2+16x\\=16x^2+16x^2-32x^2+8x-24x+16x+1+9\\=8x-24x+16x+1+9\\=1+9\\=10$