Question

poor favoor necesito ayudaa c. (x^3+6x^2+14x+24) ÷ (x+4) d. (2x^3-5x^2-30x+11)/(x+3)

Answer 1

Explicación paso a paso:

c) (x^3+6x^2+14x+24) ÷ (x+4)

$\frac{x^3+6x^2+14x+24}{x+4}\\=\frac{\left(x+4\right)\left(x^2+2x+6\right)}{x+4}\\=x^2+2x+6$

d. (2x^3-5x^2-30x+11)/(x+3)

$\frac{\left(2x^3-5x^2-30x+11\right)}{\left(x+3\right)}\\=2x^2+\frac{-11x^2-30x+11}{x+3}\\=2x^2-11x+\frac{3x+11}{x+3}\\=2x^2-11x+3+\frac{2}{x+3}$