Question

resolver
3logx-log32=logx/2

Answer 1

Respuesta:

3logx-log32 = log x-log 2

Log x³ - log 32 = log x - log 2

Logx³ - log x = log32 - log2

Log x³/x = log 32/2

Log x² = log 16

X² = 16

X² = 4²

X = 4

Explicación paso a paso: