Question

caso de factorizacion ayudenme a resolver 16a^{2} -(2a^{2}+3)^{12}[/tex] ayudenme

Answer 1

Respuesta:

(4a+(2a^{2}+3)^{6})*(4a-(2a^{2}+3)^{6})

Explicación paso a paso:

$16a^{2} -(2a^{2}+3)^{12}$

$(2a^{2}+3)^{6} =b$

$16a^{2} -b^{2}\\---(x+y)*(x-y)=x^{2}-y^{2}\\(4a+b)* (4a-b)$

$(4a+(2a^{2}+3)^{6})*(4a-(2a^{2}+3)^{6})$