Question

Si: A(x;y)=x^2+y^2-6 | B(x;y)=x^2-y^2+7 Determina F= A(x;y) + B(x;y)

Answer 1

Respuesta:

$(x^{2}+y^{2}-6)+( x^{2}-y^{2}+7)\\x^{2}+y^{2}-6+x^{2}-y^{2}+7\\x^{2}+x^{2}+y^{2}-y^{2}+7-6\\2x^{2}+1$

F= $2x^{2} +1$